Jim sold 396 tickets for a school play. Student tickets cost $3 and adult tickets cost $4. Jim sales totaled $1385. How many adult tickets and student tickets did jim sell?

Step-by-step explanation:

Let "a" represent the number of adult tickets sold. Then 396-a s the number of student tickets sold. Total revenue is ...

  4a +3(396 -a) = 1385

  a + 1188 = 1385 . . . eliminate parentheses, collect terms

  a = 197 . . . . . . . . . subtract 1188. This is the number of adult tickets.

  395-a = 199 . . . . . student ticket sold

Jim sold 197 adult tickets and 199 student tickets.

199 student tickets and 197 adult tickets

Step-by-step explanation:

First we have to make 2 equations, one for total entries and one for total money

the x and y represent the number of students and adults

x = student        y = adults

x + y = 396

x * $3 + y * $4 = $1386

now let's clear the x of one of the equations

x + y = 396

x = (396 - y)

and replace x with what is the same in the other equation

x * $3 + y * $4 = $1386

(396 - y) * $3 + y * $4 = $1386

we solve to find y

(396 - y) * 3 + y * 4 = 1386

1188 - 3y + 4y = 1386

-3y + 4y = 1385 - 1188

y = 197

to know x we replace y with the value it gave us in the first equation

x = (396 - y)

x = (396 - 197)

x = 199

so we have to

x = 199

y = 197

199 studenttickets and 197 adult tickets

1

step-by-step explanation:

it's the only multiple of both and the least

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3