During the first 13 weeks of the television season, the Saturday evening 8:00 P. M. to 9:00 P. M. audience proportions were recorded as ABC 30%, CBS 26%, NBC 22%, and independents 22%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 91 homes, CBS 68 homes, NBC 83 homes, and independents 58 homes. Test with to determine whether the viewing audience proportions changed. Compute the value of the test statistic (to 2 decimals).

The value of the test statistic is 6.642.

Step-by-step explanation:

A Chi-square test for Goodness of fit will be used to determine whether the viewing audience proportions changed.

The hypothesis is defined as:

H₀: The viewing audience proportions has not changed.

Hₐ: The viewing audience proportions has changed.

The test statistic is:

Here,

O = observed frequencies (O - E)²

E = expected frequencies = n × p

The table below shows the observed and expected frequencies.

Compute the test statistic value as follows:

Thus, the value of the test statistic is 6.642.

sorry not sure

step-by-step explanation:

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: