Mathematics, 07.03.2020 03:43 misstaejailicious200

In 2001 a national vital statistics report indicated that about 3% of all births produced twins. Is the rate of twin births the same among very young mothers? Data from a large hospital found only 7 sets of twins were born to 469 teenage girls.

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Answer from: starajaclark1429

$z=\frac{0.0149 -0.03}{\sqrt{\frac{0.03(1-0.03)}{469}}}=-1.917$

p_v =2*P(z

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis that the true proportion of twins is 0.03 or 3%

Step-by-step explanation:

Data given and notation

n=469 represent the random sample taken

X=7 represent the number of twins

$\hat p=\frac{7}{469}=0.0149$ estimated proportion of twins

p_o=0.03 is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.03.:

Null hypothesis: p=0.03

Alternative hypothesis: $p \neq 0.03$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value p_o .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.0149 -0.03}{\sqrt{\frac{0.03(1-0.03)}{469}}}=-1.917$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

p_v =2*P(z

Answer from: Quest

8y^50

step-by-step explanation:

Answer from: Quest

step-by-step explanation:

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In 2001 a national vital statistics report indicated that about 3% of all births produced twins. Is...