The data below are the gestation periods, in months, of randomly selected animals and their corresponding life spans, in years.

Gestation, x 8 2.1 1.3 1 11.5 5.3 3.8 24.3
Life span, y 30 12 6 3 25 12 10 40

a. Find the equation of the regression line for the given data. Round the line values to the nearest two decimal places. Show your work.

b. Using the equation found in part a, predict the life span when the gestation is 10 months. Round to the nearest absence.

(a) The regression line is: y = 6.343 + 1.523 x

(b) For a gestation period of 10 months, the life span is 22 years.

Step-by-step explanation:

The regression line is of the form: y = a + b x.

Here,

y = dependent variable = life span of animals

x = independent variable = gestation periods

a = intercept

b = slope

(a)

Compute the value of intercept as follows:

The intercept is 6.343.

Compute the value of slope as follows:

The slope is 1.523.

The regression line is:

y = 6.343 + 1.523 x

(b)

Foe x = 10 compute the value of y as follows:

Thus, for a gestation period of 10 months, the life span is 22 years.

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

the answer is $42.96

step-by-step explanation: