Passes through (-3,0) (-1,0) (-5,-16)
its graphing quadratics HELP

y=-2x^2-8x-6

Step-by-step explanation:

We already have two x intercepts (-3,0) and (-1,0):

(-3,0) is the solution to x+3=0

(-1,0) is the solution to x+1=0

So what we have so far is (x+3)(x+1)=y

Now we do (x+3)(x+1)*?=y

Plug in (-5,-16):

(-5+3)(-5+1)*x=-16

(-2)(-4)*x=-16

8*x=-16

x=-2

So the equation is y=(x+3)(x+1)*-2 which is y=-2x^2-8x-6

Another possible graph is y=(x+1)(x+3)(x+3) or y=x^3+7x^2+15x+9

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

it shoild be o

step-by-step explanation: