If -4 is a root of the equation x^2+px-4=0 and the equation x^2+px+q=0 has equal roots, find the value of p and q

p = 3, q = 2.5

Step-by-step explanation:

Given that x = - 4 is a root of the equation, then

(- 4)² - 4p - 4 = 0, that is

16 - 4p - 4 = 0

12 - 4p = 0 ( subtract 12 from both sides )

- 4p = - 12 ( divide both sides by - 4 )

p = 3

Also given that the equation x² + px + q = 0 has equal roots

Thus the value of the discriminant b² - 4ac = 0

Here a = 1, b = p and c = q, thus

p² - 4q = 0 ← substitute p = 3 from above into the equation

9 - 4q = 0 ( subtract 9 from both sides )

- 4q = - 9 ( divide both sides by - 4 )

q = 2.5

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

the answer is 96 degrees

step-by-step explanation:

you have to realize that a line equals 180 degrees