Mathematics, 06.03.2020 23:42 SKYBLUE1015
Suppose we have 14 red balls and 14 green balls as in the previous exercise. Show that at least two pairs, consisting of one red and one green ball, have the same value. What about 13 red balls and 14 green balls
Answers: 2
Mathematics, 21.06.2019 21:00
The sum of the first eight terms of an arithmetic progression is 9m + 14. the fifth term of the06 progression is 2m - 6, where m is a constant.given that the first term of the progression is 26,find the value of the common difference, d and thevalue of m.
Answers: 1
Mathematics, 22.06.2019 01:10
Evaluate 8x2 + 9x β 1 2x3 + 3x2 β 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 β 2x = x(2x2 + 3x β 2) = x(2x β 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the formβ 8x2 + 9x β 1 x(2x β 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x β 1)(x + 2), obtaining 8x2 + 9x β 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x β 1).
Answers: 3
Suppose we have 14 red balls and 14 green balls as in the previous exercise. Show that at least two...
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