Elijah drew a triangle that has one side longer than the other two. What must be true about the lengths of the sides of Elijah’s triangle?
A: The sum of the two shorter side lengths must be less than the length of the longest side
B: The sum of the two shorter side lengths must be greater than the length of the longest side
C: The product of the two shorter side lengths must be less that the length of the longest side
D: The product is the two shorter side lengths must be greater than the length of the longest side.

answer:

B.

Step-by-step explanation:

both sides have to be greater andyeah

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

step-by-step explanation: