What is the equation of a circle with center (1, -4) and radius 2?

The answer to your question is letter C

Step-by-step explanation:

Data

Center = (1, -4)

radius = 2

Formula

              (x - h)² + (y - k)² = r²

h = 1

k = -4

r = 2

Substitution, for the substitution, change the original signs of h and k.

             (x - 1)² + (y + 4)² = 2²        

Simplification

             (x - 1)² + (y + 4)² = 4

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answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: