A group of 12 people is traveling in three vehicles. If 4 people ride in each vehicle, in how many different ways can the people be assigned to the vehicles?

So, exist 34650 different ways.

Step-by-step explanation:

We know that a group of 12 people is traveling in three vehicles. We know that  4 people ride in each vehicle.

So, for the first car we choose 4 people out of 12. Then from the remaining 8 people we choose 4 people for the second car. While the remaining 4 people will go into the third car.

Therefore, we get

So, exist 34650 different ways.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

the answer is 0.071

good luck! : d