Please help.. I don't understand this question and the assignment is due tomorrow.

y = 7 csc(½ x) − 2

Step-by-step explanation:

General form of a cosecant function is:

y = A csc(2π/T x + B) + C

where A is the amplitude, T is the period, B is the horizontal offset ("phase shift"), and C is the vertical offset ("midline").

The range is (-∞, -9] [5, ∞), so the midline is halfway between -9 and 5.

C = (-9 + 5) / 2

C = -2

The amplitude is half the difference between -9 and 5.

A = |-9 − 5| / 2

A = 7

The period is twice the distance between consecutive asymptotes.

T = 2 (2π − 0)

T = 4π

So far, we have:

y = 7 csc(½ x + B) − 2

We know there is an asymptote at x = 0.  Cosecant is undefined at multiples of π, so:

½ (0) + B = kπ

B = kπ

B is any multiple of π.  The simplest choice is B = 0.

y = 7 csc(½ x) − 2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b