Please please help...please:(

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.9t^2 + 217t + 185.

Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?

The rocket splashes down afterseconds.

How high above sea-level does the rocket get at its peak?

The rocket peaks atmeters above sea-level

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

the answer is a if my teacher taught me correct

if i put something wrong your not gonna like it so rather not say nothing.