Solve this quadratic equation using the quadratic formula.
2x^2 - 10x + 7 = 02x2 - 10x + 7 = 0

I'm assuming the equation is:

2x^2 -10x +7 = 0

x = (-b +- sqr root (b^2 - 4ac)) / 2a

x = (--10 +-sqr root (100 -4*2*7)) / 4

x = (10 +- sqr root (44)) / 4

x1 = (10 + 6.6332495807 ) /4

x1 = 16.6332495807 / 4

x1 = 4.1583123952

x2 =(10 - 6.6332495807 ) /4

x2 = 3.3667504193  / 4

x2 = 0.8416876048

Step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: