Ming throws a stone off a bridge into a river below.

The stone's height (in meters above the water), 3 seconds after Ming threw it, is modeled by:

h(x) = -5(x - 1)2 + 45

How many seconds after being thrown will the stone reach its maximum height?

Please help!

In 1 seconds after being thrown will the stone reach its maximum height.

Step-by-step explanation:

Given : Ming throws a stone off a bridge into a river below.  The stone's height (in meters above the water), 3 seconds after Ming threw it, is modeled by : .

To find : How many seconds after being thrown will the stone reach its maximum height?

Solution :

The maximum height is attain by getting the vertex of the model.

The vertex form of the quadratic equation or parabola is

Where, (h,k) are the vertex.

On comparing with the given model,

a=-5, h=1 and k=45

The vertex of the equation is (h,k)=(1,45).

Now the maximum height is 45 m and number of second is 1 sec.

Therefore, In 1 seconds after being thrown will the stone reach its maximum height.

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.