A particle is moving horizontally along the x-axis. Its position (in ft) is: s(t)=t^3-18t^2+33t+14 where t is in sec.
Find the time at which the particle switches from moving left to moving right.
t= ___ sec.

t=11 sec

Step-by-step explanation:

The position of the particle moving along the x-axis is given by:

The velocity is given by:

If s'(t)>0 then the particle is moving right.

This means that the particle is moving left when

The particle changes direction at time t=1 or t=11

step-by-step explanation:

no solution.