Help plswith 4 & 5:/

4) J

5) D

Step-by-step explanation:

4) 416 = 2x² - 6x

2x² - 6x - 416 = 0

x² - 3x - 208 = 0

x² - 16x + 13x - 208 = 0

x(x - 16) + 13(x - 16) = 0

(x - 16)(x + 13) = 0

x = 16, -13(not possible)

So 16 rows

5) y = a(x - h)² + k

y = a(x - 3)² - 7

When x = 1, y = -10

-10 = a (1 - 3)² - 7

-10 = 4a - 7

4a = -3

a = -¾

y = -¾(x - 3)² - 7

b

step-by-step explanation:

the word superfluous means unnecessary

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?