Find the area of the ring-the shaded region

The area of the (ring) - the shaded region is 75.36 in²

Solution:

The value of π = 3.14

Radius of the inner circle = 5 in

Area of the inner circle = πr²

                                       = π × 5²

Area of the inner circle = 25π

Radius of the outer circle = (5 + 2) = 7 in

Area of the outer circle = πr²

                                       = π × 7²

Area of the outer circle = 49π

Area of the shaded ring = Area of the outer circle – Area of the inner circle

                                        = 49π – 25π

                                        = 24π

                                        = 24 × 3.14

                                        = 75.36 in²

The area of the (ring) - the shaded region is 75.36 in².                                

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

60

step-by-step explanation:

every triangle measures a total of 120 degrees. you have to find angle c. we know that isosceles triangles angles are equal. 60 degrees plus 60 degrees gives you 120.