The equation r(t)= (3t+9)i+(sqrt(2)t)j+(t^2)k is the position of a particle in space at time t. Find the angle between the velocity and acceleration vectors at time t=0
What is the angle? radians

, for all

Step-by-step explanation:

The velocity vector is found by deriving the position vector depending on the time:

In turn, acceleration vector is found by deriving the velocity vector depending on time:

Velocity and acceleration vectors at are:

Norms of both vectors are, respectively:

The angle between both vectors is determined by using the following characteristic of a Dot Product:

Given that cosine has a periodicity of . There is a family of solutions with the form:

, for all

2.

according to newton’s cannonball model, what happens if the cannonball's velocity is enough to overpower the pull of earth’s gravitystep-by-step explanation:

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )