A researcher claims that the proportion of people who are right-handed is greater than 70%. To test this claim, a random sample of 600 people is taken and its determined that 424 people are right-handed.

The following is the setup for this hypothesis test:

{H0:p=0.70

Ha:p>0.70

Find the test statistic for this hypothesis test for a proportion.

The test statistic is 0.53.

Step-by-step explanation:

z = (proportion mean - population proportion) ÷ sqrt(pq/n)

proportion mean = x/n = 424/600 = 0.71

population proportion (p) = 70% = 0.70

q = 1 - p = 1 - 0.70 = 0.30

n = 600

z = (0.71 - 0.70) ÷ sqrt(0.70×0.30/600) = 0.01 ÷ sqrt (3.5×10^-4) = 0.01 ÷ 0.019 = 0.53

step-by-step explanation:

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%