Condider the following equation f(x)=x^2+4/(4x^2-4x-8)

x^2+4/4(x-2)(x+1)

Step-by-step explanation:

I assume you're trying to put it in a simplified form.

The top is not factorable so you can focus on the bottom

take out the greatest common factor of 4 on the bottom

4(x^2-x-2)

Then factor this expression

your factors should be -2 and 1

so 4(x-2) (x-1)

Final

(x^2+4)/(4(x-2)(x-1))

the square root of what number? if you add that, then someone will probably answer the question.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3