If f(x)=4-x^2 and G(x)=6x, which expression is equivalent to (g-f)(3)?

23

Step-by-step explanation:

Subtract the function f(x) from the function g(x):

g(x)= 6x

- f(x)=4 - x^2

(g-f)(x) = 6x - 4 + x^2

Now replace x with the given value 3:

(g - f)(3) = 6(3) - 4 + (3)^2

              = 18    -4   + 9 = 23

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9

step-by-step explanation:

infinity is the answer