If you are given the graph of h(x)=log6x, how could you graph m(x)=log6(x+3)?

Translate each point of the graph of h(x) 3 units up.
Translate each point of the graph of h(x) 3 units down.
Translate each point of the graph of h(x) 3 units right.
Translate each point of the graph of h(x) 3 units left.

last option.

Step-by-step explanation:

There are several transformations for a function f(x). Some of them are shown below:

1. If , then the function is translated "k" units up.

2. If , then the function is translated "k" units down.

3. If , then the function is translated "k" units left.

4. If , then the function is translated "k" units right.

In this case you have the following function:

And the function m(x) is obtained by transformating the function h(x). This function is:

Then, based on the transformatios shown before, you can identify that:

Therefore, you can determine that you could graph the function   by translating each point of the graph of the function h(x) 3 units left.

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

the correct option is b

step-by-step explanation: