What is the solution to the following system? X+ 2y + Z = 9 %-Y+32 = 13 2z = 10 x = 10, y = 2, z = 5 x= -4, y = 2, z = 5 x = 0, y = 2, z = 5 x = 4, y = 6, z = 5
I am trying to finish a challenge. p.s. "STREAKS".
Step-by-step explanation:
Answer from: Quest
Best answer that i found on yahoo ok set : x= length of 2nd piece in cm x- 3= length of 1st piece in cm x-4= length of 3rd piece in cm then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20 3x - 7= 20 3x= 27 x= 9 the shortest piece is the third piece which is x- 4 x-4 9-4 = 5 the length of the smallest piece is 5 cm. the other lengths are 9 cm 6 cm
Answer from: Quest
c) 6
step-by-step explanation:
let pq = qr = rs = x, and xz = y and zu = z.
if the horizontal lines are parallel, then corresponding segments are in proportion:
substitute:
therefore 3 = y = z.
xu = y + z → xu = 3 + 3 = 6
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