The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 115 seconds and a standard deviation of 20 seconds. The fastest 10% are to be given advanced training. What task times qualify individuals for such training

c = 89.4 seconds

The time for the fastest 10 % is less than 89.4 seconds

Step-by-step explanation:

The mean value is μ = 115 seconds and the standar deviation δ = 20 seconds.

We need to find c such that

P(x<c) = 0.1 It means, C is the time for the fastest 10 %

Such that:

We find z of the normal standard table

Thus

c = 89.4 seconds

The time for the fastest 10 % is less than 89.4 seconds

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )