The weight of a product is measured in pounds. A sample of 50 units is taken from a recent production. The sample yielded ¯y= 75 lb, and we know that LaTeX: \sigmaσ2= 100 lb. Calculate a 90 percent confidence interval for LaTeX: \text{μ}

90 percent confidence interval = [72.674 ,77.326]

Step-by-step explanation:

We are given that weight of a product is measured in pounds.

A random sample of 50 units is taken from a recent production. The sample yielded y bar = 75 lb, and we know that = 100 lb.

The Pivotal quantity for 9% confidence interval is given by;

               ~ N(0,1)

where, Y bar = sample mean = 75

                 = population standard deviation = 10

                 n = sample size = 50

So, 90% confidence interval for population mean,  is given by;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < < 1.6449) = 0.90

P(-1.6449 * < < 1.6449 * ) = 0.90

P(Y bar - 1.6449 * < < Y bar + 1.6449 * ) = 0.90

90% confidence interval for = [ Y bar - 1.6449 * , Y bar + 1.6449 * ]

                                              = [ 75 - 1.6449 * , 75 + 1.6449 * ]

                                              = [ 72.674 , 77.326 ]

Therefore, 90% confidence interval for population mean is [72.674 ,77.326] .

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

one peck is 9.309 quarts

9.309x 2