What is the vertex of g(x) = 8x2 – 64x? (4, –128) (–4, –128) (4, –16) (–4, –16)

The answer is (4, -128). If the function is written in the form y = a(x – h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 - 64x in the form of a(x – h)^2 + k. g(x) = 8x^2 - 64x. g(x) = 8 * x^2 - 8 * 8x. g(x) = 8(x^2 - 8x). g(x) = 8(x^2 - 8x + 16 - 16). g(x) = 8((x^2 - 8x + 16) - 16). g(x) = 8((x - 4)^2 - 16). g(x) = 8(x - 4)^2 - 8 * 16. g(x) = 8(x - 4)^2 - 128. The function is now in the form a(x – h)^2 + k, where a = 8, h = 4, and k = -128. Thus, the vertex is (4, -128).

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