Does 131 appear in the sequence 6n-1

Step-by-step explanation:

6n - 1 = 131 ⇔ 6n = 132 ⇔ n = 132÷6 = 22

then 131 is the 22 term of the sequence

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2