Mathematics, 02.03.2020 21:24 codyshs160

An object is propelled off of a platform that is 75 feet high at a speed of 45 feet per second (ft./s). The height of the object off the
ground is given by the formula h(t)= - 16t^2 + 45t + 75, where h(t) is the object's height at time (t) seconds after the object is propelled. The downward negative pull on the object is represented by - 16t^2. Solve for t.

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An object is propelled off of a platform that is 75 feet high at a speed of 45 feet per second (ft./...

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