Which function has real zeros at x = −10 and x = −6? f(x) = x2 16x 60 f(x) = x2 − 16x 60 f(x) = x2 4x 60 f(x) = x2 − 4x 60

Would assume the function is a quadratic function. It is degree 2.

The zeros or roots are x = - 10, and x = -6.

For quadratic:

x² - (sum of roots)x + product = 0

x² - (-10 + -6)x + (-10)*(-6) = 0

x² - (-16)x + (60) = 0

x² + 16x + 60 = 0

f(x) = x² + 16x + 60 

Tbh idk i just getting points so i can ask questions