I NEED HELP OF THIS! Brian "bicycle kicked" a soccer ball up from a height of 4ft off the ground with an initial upward velocity of 34 feet/sec. As the ball was coming down, Mike jumped up and at 8 ft off the ground, headed it into the goal and win the game. How long did it take for the ball to come down and reach Mike's head? Use the formula h = -16t^2 +vt + s PLEASE!

  2 seconds

Step-by-step explanation:

The formula h = -16t^2 +vt +s gives the vertical height (in feet) at time t (in seconds) for an object with an initial vertical velocity (in ft/s) of v and an initial height (in ft) of s. The problem statement tells us the ball's initial velocity is v=34 and the initial height is s=4.

Then the equation is ...

  h = -16t^2 +34t +4

We want to find the value of t when h=8. There will be two solutions, one when the ball is going up, and the other when the ball is coming down. We are interested in the second solution.

  8 = -16t^2 +34t +4

  16t^2 -34t +4 = 0 . . . . . subtract the right side of the equation to put it into standard form

  (16t -2)(t -2) = 0 . . . . . . factor the equation

Solutions are values of t that make the factors zero:

  t = 2/16  or  t = 2

It takes 2 seconds for the ball to come down to meet Mike's head.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.