The 5th term of an AP is 11 and the 9th term is 7. Find the 16th term

16th term is 0.

S1ep-by-step explanation:

5th term = a1 + d(5 - 1) = 11    where a1 = first term and d = common difference

9th term = a1 +d(9 - 1) = 7    where a1 = first term and d = common difference.

a1 + 4d = 11

a1 + 8d = 7

Subtracting:

4d - 8d = 11-7

-4d = 4

d = -1.

So a1 = 11 - 4(-1) = 15.

16th term = 15 - 1(16-1)

= 15 - 15

= 0.

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5

is there a question here?

step-by-step explanation: