Solve the system of equations using substitution. 3 multiplied by y equals negative the quantity 1 divided by 2 end of quantity multiplied by x plus 2. y equals negative x plus 9. a. (20, –4) b. (10, –1) c. (3, 6) d. (–1, 8)

3y = -1/2x + 2 . . . . . . . . (1)
y = -x + 9 . . . . . . . . (2)
substituting (2) into (1), we have
3(-x + 9) = -1/2x + 2
-3x + 27 = -1/2x + 2
-1/2x + 3x = 27 - 2
5/2x = 25
x = (2 x 25)/5
x = 10
From (2)
y = -10 + 9
y = -1
solution (10, -1)