A box can hold a maximum of 8 cans. You have 50 cans to put in boxes. What is the smallest number of boxes you need to store all of the cans in boxes?

Using proportions, it is found that the smallest number of boxes you need to store all of the cans in boxes is of 7.

The rule of three is:

1 box - 8 cans

x boxes - 50 cans

Applying cross multiplication:

Rounding up, 7 boxes are needed.

You can learn more about proportions at link

7boxes

Step-by-step explanation:

A box can hold a maximum of 8 cans

You have a total of 50 cans

The problem here is to determine the minimum number of boxes that can hold the 50 cans

Let the minimum number of boxes = y

The minimum required will be such that:

The Product of The number of cans X Number of Required boxes ≥50

8y≥50

y≥50/8

y≥6.25

Since a box have a fractional value, the minimum number of boxes required to store 50 cans will be the nearest whole number which in this case is 7.

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

cosine

step-by-step explanation: