HELP PLEASE
An airplane is heading north at an airspeed of 700 km/hr, but there is a wind blowing from the southwest at 80 km/hr.

The plane will end up flying ___?___ degrees off course
The plane's speed relative to the ground will be ___?__ km/hr

The plane will end up flying 5.02°.

The plan's speed relative to the ground will be 645.91 km/hr.

Solution:

Use the cosine formula,

Substitute the given values in the formula,

Taking square root on both sides, we get

R = 645.91 km/hr

This is the grouped speed of the aircraft.

To find θ use sine rule.

Do cross multiplication, we get

sin θ = 0.0875

θ = 5.02°

This is known as the drift angle and is the correction the pilot should apply to remain on course.  

The heading is the direction the aircraft's nose is pointing which is

The track is the actual direction over the ground which is θ = 5.02°

An alternative method to this would be to separate each vector into vertical and horizontal components and add.

The resultant can be found using Pythagoras.

we need the options

step-by-step explanation:

i would pic false cause it goes down towards negative

step-by-step explanation: