The length of a rectangle is 7 ft longer than twice the width. If the perimeter is 92 ft find the length and width of the rectangle

Width of the rectangle is 13 ft and length of the rectangle is 33 ft

Step-by-step explanation:

Step 1:

Given perimeter of the rectangle = 92 ft. Let the width be x, then the length of the rectangle = 2x + 7. Use the formula for perimeter of a rectangle = 2(length + width) to find the dimensions.

92 = 2(2x + 7 + x) = 2(3x + 7) = 6x + 14

⇒ 92 = 6x + 14

⇒ 78 = 6x

⇒ x = 78/6

∴ x = 13 ft

⇒ Width of the rectangle = 13 ft

∴ Length of the rectangle = 2x + 7 = 26 + 7 = 33 ft

your answer is a

step-by-step explanation:

plzplzplzplzplz mark brainliest i need it.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47