What is the equation of the circle with center (1, 1) that passes through the point (−3, 4)?

 (x - 1)² + (y - 1)² = 25

Step-by-step explanation:

The formula for a circle is     (x - h)² + (y - k)² = r²     where

Typically, you are given the center and the radius.  In this problem, you are given (x, y) so you must plug that into the equation to find r².

Given: (x, y) = (-3, 4)   and   (h, k) = (1, 1)

                       (-3 - 1)² + (4 - 1)² = r²

                         (-4)²    +   (3)²   = r²

                          16      +    9     = r²

                                  25         = r²

Next, input (h, k) and r² into the equation

                  (x - 1)² + (y - 1)² = 25

1. 22

2. 1

3. 7

4. 18

step-by-step explanation

e2020 got it right

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°