Please?
Find the constant $k$ such that the quadratic $2x^2 + 3x + k$ has a double root.
I'll mark the first actually helpful answer the brainliest. Just type the answer, I don't need an explanation...

  k = 9/8

Step-by-step explanation:

For a root with multiplicity 2, the discriminant must be zero. For quadratic ax^2 +bx +c, the discriminant is ...

  d = b^2 -4ac

For your quadratic, a=2, b=3, c=k, so you want ...

  3^2 -4(2)(k) = 0

  9 -8k = 0

  k = 9/8

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.