If f (x) = one-ninth x minus 2, what is f-1(x)

(x) = 9x + 18

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = x - 2 ( add 2 to both sides )

y + 2 = x

Multiply through by 9 to clear the fraction

9y + 18 = x

Change y back into terms of x

(x) = 9x + 18

f-1(x) = 9x + 18.

Step-by-step explanation:

Let y = 1/9 x - 2

1/9 x = y + 2

x = (y + 2) / 1/9

x=  9(y + 2)

x = 9y + 18

Now replace the x by the inverse f-1(x) and the y by x:

f-1(x) = 9x + 18.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

1. minimum

2. 6400

3. eight

hope this !