Find k such that f(x) is continuous at x=30
Is this how you would solve it?
1.25(30)=37.5
1.10(30)+k=37.5
33+k=37.5
k=37.5-33
k=4.5
??

this is correct

Step-by-step explanation:

f continous in x=30 means that it should be the same value for 1.25 x 30 and 1.10 x 30 + k so k =4.5

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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