A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. a. Write an equation that gives the height (in feet) of the grasshopper as a function of the time (in seconds) since it leaves the ground. b. After how many seconds is the grasshopper 1 foot off the ground?

The grasshopper will be at 1 foot after 1.50 seconds.

Step-by-step explanation:

a). A grasshopper jumps straight up with an initial vertical velocity = 8 feet per second

From the equations of vertical motion,

Here h = height of the grasshopper at the time 't'

u = initial velocity

g = Acceleration due to gravity

t = duration or time

Now we plug in the value of initial velocity in this equation.

b). In this part we have to calculate the time when the grasshopper is 1 foot off the ground.

from the expression of part (a),

t =

 =

 =

 = 1.50, (-0.14) seconds

But the time can not be negative, so the grasshopper will be at 1 foot after 1.50 seconds.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: