How do you solve (2x-7)(5x+3)=0

Step-by-step explanation:

First I do it as separate equations 2x-7=0 and 5x+3=0. In this equation you get two answers so you first answer 2x-7=0

2x-7=0

    +7   +7

2x=7

/2   /2

x=7/2

Then do 5x+3=0

                     -3  -3

                5x=-3

                    /5 /5

                x=  -3/5

Then you can check by putting them back in.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

i don't even know man. edge inuity be messing with us. i had to ask a question too.