Let Ab e an invertiblen×nmatrix, and let B be ann×pmatrix. Show thatthe equationAX=Bhas a unique solutionA−1B. Hint: You need to show thatA−1Bis a solution, and that there is no other solution. You might do this secondpart by making an argument each column ofB

In fact,  is a solution to the equation AX = B. Let me show you.

Step-by-step explanation:

Step 1 .

Remember that there's a very special x matrix, called "the identity matrix", we denote it as .

That matrix is special because

                                    *(Any matrix)  = Any matrix,

So, when I say, "Any matrix", that literally means, "Any martrix", well, any x matrix. Therefore;

                                                     *A = A

Step 2.

Remember that A is invertible if there exist a matrix such that

                                                      * =   .

 is just the name of it, the most important is the property I just mentioned.

Step 3.

Now, to show that,  we just have to show that is a solution of , in other words we have to show that,  

Notice that

Therefore, is a solution of .

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )