Two factory plants are making TV panels. Yesterday, plant A produced 6000 panels. Two percent of the panels from plant A and 6% of the panels from plant B were defective. How many panels did plant B produce, if the overall percentage of defective panels from the two plants was 5%

1% of 4000 + 4% of B = 2% of (4000 + B)

40 + 0.04*B = 0.02( 4000 + B)

40 + 0.04* B = 80 + 0.02*B

40 + 0.04*B - 80 - 0.02B = 0

0.02*B - 40 = 0

0.02*B = 40

2B = 4000

B = 2000

CHECK:

1% of 4000 + 4% of 2000 = 40 + 80 = 120 defectives

4000 + 2000 = 6000

120 out of 6000 = 120/6000 = 12/600 = 1/50 = 2%

Plant A produces 4000 panels and 1% of them , or 40, are defective.

Plant B produces 2000 panels and 4% of them, or 80, are defective.

Plz mark brainliest

Step-by-step explanation:

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: