Lines a and b are parallel. When they are cut by transversals, they form a triangle Parallel lines a and b are cut by transversals s and t to form a triangle. Angle 1 is 90 degrees, angle 2 is 62 degrees, and angle 3 is unknown. What is Measure of angle 3 ?

Therefore, the angle 3 have 28 degrees.

Step-by-step explanation:

We know that the lines a and b are parallel. When they are cut by transversals, they form a triangle. Parallel lines a and b are cut by transversals s and t to form a triangle. Angle 1 is 90 degrees, angle 2 is 62 degrees.

We know that the number of degrees in a triangle equals 180.

We get:

Therefore, the angle 3 have 28 degrees.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.