Consider a monohydrid cross, which is an Aa by Aa cross, where the expected outcome of genotype frequencies for the offspring is 1 to 2 to 1 using a Punnett square. You have observed 300 offspring with 80 AA, 165 Aa, and 55 aa genotypes. Please calculate the chi-squared statistic for a test of the null hypothesis that the observed genotype counts in the offspring are equal to their expectation of 1 to 2 to 1.