subject
Mathematics, 27.02.2020 02:04 mahalabear8120

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 21.06.2019 14:30
Can you simplify 4/7? 24 points will be awarded!
Answers: 2
question
Mathematics, 21.06.2019 15:00
What is the multiplicative rate of change of the exponential function shown on the graph?
Answers: 2
question
Mathematics, 21.06.2019 15:30
Kylie explained that (-4x+9)^2 will result in a difference of squares because (-4x+9)^2 (-4x+9)^2 =(-4x)^2+(9)^2=16x^2+81
Answers: 3
question
Mathematics, 21.06.2019 18:30
Angela took a general public aptitude test and scored in the 88th percentile for aptitude in accounting. what percentage of the scores were at or below her score?
Answers: 2
You know the right answer?
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠a...
Questions
question
Mathematics, 11.08.2021 21:00