Frank got a gift for his sister and put it in a shoebox.

Now, he wants to wrap it with wrapping paper. If the length of the shoebox measures 11 in, the width measures 6 in, and the height measures 5 in, how much wrapping paper does he need to cover the shoebox?

A.

604 sq in

B.

151 sq in

C.

302 sq in

D.

453 sq in

The correct answer is option C.

Step-by-step explanation:

Length of shoe box = l = 11 inches

Width of the shoes box = w = 6 inches

Height of the shoe box = h = 5 inches

Wrapping paper required t cover the shoe box will be equal to the total surface area of the shoe box.

Shoe box = Cuboid

Total surface area of the cuboid = 2(lw+wh+hl)

Total surface area of shoe box : T

Frank will need 302 square inches of wrapping paper to cover the shoe box.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐