Assume a population has a gene with 2 alleles. All the conditions of Hardy-Weinberg equilibrium are met for this gene in this population. The frequencies of the 2 alleles are p and q. What can we predict about the frequencies of the 2 alleles, for the next 100 generations? Assume the conditions of Hardy-Weinberg equilibrium are maintained.

The answer to the question is

The frequency will remain the same as the equilibrium is attained for the next 100 generation

Step-by-step explanation:

The Hardy-Weinberg equilibrium law states that in a population, the frequencies of allele and genotype will be the same from one generation to generation (that is remain constant) where there are no evolutionary infleuncies such as inbreeding, mutation, sexual selection, natural selection, choice of mate and meiotic drive

Where f(A) = p and f(B) = q, with random mating we have the following genotype frequencies f(AA)  = p², f(BB) = q², f(AB) = pq and f(BA) = qp

Where evolutionary forces are absent, the frequencies of the p and q will remain the same as equilibrium is attained

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^