What is an equation of the line that is perpendicular to y + 1 = –3(x – 5) and passes through the point (4, -6)

just use the concept that if two lines are perpendicular then product of slopes is -1

then you can find slope of other line by using -1/m1

where m1 is slope of the line given

then for that m2.use 2 point form of a line to find it's equation which passes through (4,-6)

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: