A right triangle had a vertex at point M and a height of 5 units. There base of the triangle is on MN and is 3 units long. One of the vertices of the triangle is at M

3 ft

step-by-step explanation:

since the triangle is right use pythagoras' identity to solve for a

the square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

a² + 8² = ( )²

a² + 64 = 73 ( subtract 64 from both sides )

a² = 9 ( take the square root of both sides )

a = = 3

f(x) = y

f(-3) = -5

step-by-step explanation:

explanation:

remove parenthesis:

=

apply rule

=

multiply fractions:

=

=

divide:

=

mordancy.

y-3=-3/2(x+4)

ur very much welcome